SOLUTION: Please help me solve this question: Find the vertex and graph the parabola. y=x^2+4x+3

Algebra ->  Complex Numbers Imaginary Numbers Solvers and Lesson -> SOLUTION: Please help me solve this question: Find the vertex and graph the parabola. y=x^2+4x+3      Log On


   

Question 810518: Please help me solve this question:
Find the vertex and graph the parabola.
y=x^2+4x+3
Answer by rothauserc(4718) About Me  (Show Source):
You can put this solution on YOUR website!
y=x^2+4x+3
x coordinate of the vertex is given by -b/2a = -4/2*1 = -2
now substitute for x in the equation
y = (-2)^2 +4*(-2) + 3
y = -1
vertex is (-2, -1)
here is the graph
+graph%28+300%2C+200%2C+-5%2C+5%2C+-10%2C+10%2C+x%5E2+%2B4x+%2B3%29+