SOLUTION: The graph has a hole in the function f(x)=x-3/x^2-2x-3 where is it?
Which statement is true?
There is a hole at x = 3 and an asymptote at x = –1.
There is an asymptote at x
Algebra ->
Trigonometry-basics
-> SOLUTION: The graph has a hole in the function f(x)=x-3/x^2-2x-3 where is it?
Which statement is true?
There is a hole at x = 3 and an asymptote at x = –1.
There is an asymptote at x
Log On
Question 810079: The graph has a hole in the function f(x)=x-3/x^2-2x-3 where is it?
Which statement is true?
There is a hole at x = 3 and an asymptote at x = –1.
There is an asymptote at x = –1 and no hole.
There is a hole at x = 3 and no asymptote.
There is an asymptote at x = 3 and a hole at x = –1 Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! The graph has a hole in the function f(x)=x-3/x^2-2x-3 where is it?
f(x)=x-3/x^2-2x-3
f(x)=(x-3)/(x+1)(x-3)
There is a hole at x = 3 and an asymptote at x = –1.
(