SOLUTION: the sum of two positive integers is 40. find the two integers such that the product of the square of one number and the cube of the other number is a maximum.

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Question 810043: the sum of two positive integers is 40. find the two integers such that the product of the square of one number and the cube of the other number is a maximum.
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
the sum of two positive integers is 40. find the two integers such that the product of the square of one number and the cube of the other number is a maximum.
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Maximum of x%5E3%2A%2840-x%29%5E2
f(x)= x%5E5+-+80x%5E4+%2B+1600x%5E3
f'(x) = 5x%5E4+-+320x%5E3+%2B+4800x%5E2+=+0
x%5E2%2A%28x%5E2+-+64x+%2B+960%29+=+0
(x - 24)*(x - 40) = 0
Max at x = 24
--> 16 & 24