SOLUTION: At 9:00am, a freight train leaves Seattle traveling at 45 miles per hour. At 10:00am, a passenger train leaves th same station traveling in the same direction at 55 miles per hour.
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-> SOLUTION: At 9:00am, a freight train leaves Seattle traveling at 45 miles per hour. At 10:00am, a passenger train leaves th same station traveling in the same direction at 55 miles per hour.
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Question 80992: At 9:00am, a freight train leaves Seattle traveling at 45 miles per hour. At 10:00am, a passenger train leaves th same station traveling in the same direction at 55 miles per hour. How long will it take for the passenger train to over take the freight train? How far will they be from the station at this time? Answer by checkley75(3666) (Show Source):
You can put this solution on YOUR website! 45T=55(T-1)
45T=55T-55
45T-55T=-55
-10T=-55
T=-55/-10
T=5.5 HOURS AFTER THE FIRST TRAIN LEAVES THEY WILL MEET.
PROOF
45*5.5=55(5.5-1)
247.5=55*4.5
247.5=247.5
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