SOLUTION: I can't figure out what method you use to solve: 5sin(theta/2) = 5cos(theta/2) for all values of theta on the interval [0, 360) (in degrees)
I tried using identities, but that jus
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-> SOLUTION: I can't figure out what method you use to solve: 5sin(theta/2) = 5cos(theta/2) for all values of theta on the interval [0, 360) (in degrees)
I tried using identities, but that jus
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Question 809894: I can't figure out what method you use to solve: 5sin(theta/2) = 5cos(theta/2) for all values of theta on the interval [0, 360) (in degrees)
I tried using identities, but that just made everything messy. Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! I can't figure out what method you use to solve: 5sin(theta/2) = 5cos(theta/2) for all values of theta on the interval [0, 360) (in degrees)
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5sin(x/2)=5cos(x/2)
sin(x/2)=cos(x/2)
sin(x/2)/cos(x/2)=1=tan(x/2)
x/2=45˚, 225˚
x=90˚
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