SOLUTION: Graph Y > x^2-4x+5 Would I change this to vertex form to find the vertex? How do I find the points to graph?

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Question 809783: Graph Y > x^2-4x+5
Would I change this to vertex form to find the vertex? How do I find the points to graph?
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Graph Y > x^2-4x+5
How do I find the points to graph?
y=x^2-4x+5
complete the square
y=(x^2-4x+4)-4+5
y=(x-2)^2+1
vertex:(2,1)
parabola opens up
y-intercept: set x=0
y=5
axis of symmetry:x=2
point(4,5)
x-intercepts:none (from vertex)
This should give you enough points to graph the parabola
See graph below:
+graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C++x%5E2-4x%2B5%29+