SOLUTION: The angle of \theta is between 0 < \theta < 2\pi. Given that the terminal side of \theta passes through (5, -7) use the half angle formulas to find the following
sin(theta/2)=
Algebra ->
Trigonometry-basics
-> SOLUTION: The angle of \theta is between 0 < \theta < 2\pi. Given that the terminal side of \theta passes through (5, -7) use the half angle formulas to find the following
sin(theta/2)=
Log On
Question 809744: The angle of \theta is between 0 < \theta < 2\pi. Given that the terminal side of \theta passes through (5, -7) use the half angle formulas to find the following
sin(theta/2)=
cos(theta/2)=
tan(theta/2)= Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! The angle of \theta is between 0 < \theta < 2\pi. Given that the terminal side of \theta passes through (5, -7)
----
x = 5
y = -7
r = sqrt[25+49] = sqrt[74]
=================================
sin = y/r = -7/sqrt(74)
cos = x/r = 5/sqrt(74)
tan = y/x = -7/5
=========================
use the half angle formulas to find the following
sin(theta/2)= sqrt[(1+cos(theta))/2]
----
cos(theta/2)= sqrt[1-cos(theta))/2]
----
tan(theta/2)= sqrt[(1-cos(theta))/(1+cos(theta)]
====================
Cheers,
Stan H.
====================
(