SOLUTION: I need help finding the information for the Quadratic Equation. y= -3/4(x+4)^2-6 I need to find: Vertex: (-4,-6) is what I believe it is because h and k are the vertex Axis

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: I need help finding the information for the Quadratic Equation. y= -3/4(x+4)^2-6 I need to find: Vertex: (-4,-6) is what I believe it is because h and k are the vertex Axis       Log On


   



Question 809712: I need help finding the information for the Quadratic Equation.
y= -3/4(x+4)^2-6
I need to find:
Vertex: (-4,-6) is what I believe it is because h and k are the vertex
Axis of Symmetry: I know that x=h so would the axis be -4?
Direction of Opening : Down is what I believe it is because A is negative
Minimum or Maximum:
Value of Minimum or Maximum:


Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
parabola
focus | (-4, -19/3)~~(-4, -6.33333)
vertex | (-4, -6)
semi-axis length | 1/3
focal parameter | 2/3~~0.666667
eccentricity | 1
directrix | y = -17/3
has maximum so opening below
axis of symmetry x=-4
vertex is the maximum