Question 80960: Please help me solve this problem: Given a line containing the points (1,3), (2,4), (3,5) determine the slope-intercept form of the equation, give one additional point of this line and graph the function.
Equation of line in slope-intercept form:
Show your work here:
Give one additional point in (x,y) form that would fall on this line:
Graph the function:
Answer by checkley75(3666)   (Show Source):
You can put this solution on YOUR website! USING ANY SET OF POINTS USE THE FORMULA (Y2-Y1)/(X2-X1) TO FIND THE SLOPE THUS:
(4-3)/(2-1)=1/1=1 WHICH IS THE SLOPE.
NOW REPACE THE X & Y VALUES & THE SLOPE (m) IN THE LINE EQUATION Y=mX+b & SOLVE FOR THE Y INTERCEPT (b).
3=1*2+b
3=2+b
b=3-2
b=1
THUS THE LINE EQUATION IS
Y=X+1
ANOTHER POINT IS (4,6)
 (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, y = x +1).
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