SOLUTION: the question is to find the numerical value of one trigonometric function of x and the problem is cscx=sinxtanx+cosx but only working with one side (the harder side) what a

Algebra ->  Trigonometry-basics -> SOLUTION: the question is to find the numerical value of one trigonometric function of x and the problem is cscx=sinxtanx+cosx but only working with one side (the harder side) what a      Log On


   



Question 809599: the question is to find the numerical value of one trigonometric function of x and the problem is cscx=sinxtanx+cosx but only working with one side (the harder side) what are my steps?

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
find the numerical value of one trigonometric function of x and the problem is cscx=sinxtanx+cosx
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csc(x) = (sin(x))*(sin/cos) + cos
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csc(x) = (sin^2(x)+cos^2(x)/cos(x)
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csc(x) = 1/cos(x)
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Note: The right side is the secant, not the cosecant.
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Cheers,
Stan H.
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