SOLUTION: The question is... 1. Two inequalities follow: -26<4k-2 and 2k-1<5 A. Write a compound inequality to combine the inequalities shown previously. An

Algebra ->  Inequalities -> SOLUTION: The question is... 1. Two inequalities follow: -26<4k-2 and 2k-1<5 A. Write a compound inequality to combine the inequalities shown previously. An      Log On


   



Question 809572: The question is...
1. Two inequalities follow:
-26<4k-2 and 2k-1<5
A. Write a compound inequality to combine the inequalities shown previously.

Answer:
B. Solve the compound inequality for values of k. Show your work. Write your final answer as one inequality.
--------------------------------------------------------------------------------
The work I have so far is:
1. Simplify the individual equations on either side of the "and". This would leave you with -24<4k and 2k<6. Then you would simplify each of them even further by dividing. This will leave you with -6 Written out what I have done so far is...
-26<4k-2 and 2k-1<5
+2 +2 +1 +1
--------------------
-24<4k and 2k<6
/4 /4 /2 /2
--------------------
-6 < k and k < 3
This would leave you with -6 < k < 3.
_______________________________________________________________________________
I believe that the work I have done so far is the answer to the second part of the original question (Pt. B). Is it? And if it is, how do I use this to find Pt. A or how do I figure out Pt. A not using my work already?

Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
-26%3C4k-2 and 2k-1%3C5

The first one:
-26%2B2%3C4k
-24%3C4k
-6%3Ck

The second one:
2k%3C5%2B1
2k%3C6
k%3C6%2F2
k%3C3

Combining these into one gives you highlight%28-6%3Ck%3C3%29

The wording in Part A is troublesome. Where are the previous inequalities?
Parts A and B are the same thing.

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
The question is...
1. Two inequalities follow:
-26<4k-2 and 2k-1<5
A. Write a compound inequality to combine the inequalities shown previously.

Answer:
B. Solve the compound inequality for values of k. Show your work. Write your final answer as one inequality.
--------------------------------------------------------------------------------
The work I have so far is:
1. Simplify the individual equations on either side of the "and". This would leave you with -24<4k and 2k<6. Then you would simplify each of them even further by dividing. This will leave you with -6 Written out what I have done so far is...
-26<4k-2 and 2k-1<5
+2 +2 +1 +1
--------------------
-24<4k and 2k<6
/4 /4 /2 /2
--------------------
-6 < k and k < 3
This would leave you with -6 < k < 3.
_______________________________________________________________________________
I believe that the work I have done so far is the answer to the second part of the original question (Pt. B). Is it? And if it is, how do I use this to find Pt. A or how do I figure out Pt. A not using my work already?

- 26 < 4k - 2 and 2k - 1 < 5

A.
1st inequality
- 26 < 4k - 2

2(- 13) < 2(2k - 1) ---- Factoring out GCF, 2

- 13 < 2k - 1

We now have the following compound inequality: highlight_green%28-+13+%3C+2k+-+1+%3C+5%29

B.
Solve for k

You can do the check!!

Send comments, “thank-yous,” and inquiries to “D” at MathMadEzy@aol.com. Further help is available, online or in-person, for a fee, obviously.

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