SOLUTION: fine the slope intercept form of the equation of the line that passes through the point (-9,5) and is perpendicular to the line 7x+8y=2

Algebra ->  Linear-equations -> SOLUTION: fine the slope intercept form of the equation of the line that passes through the point (-9,5) and is perpendicular to the line 7x+8y=2      Log On


   



Question 809479: fine the slope intercept form of the equation of the line that passes through the point (-9,5) and is perpendicular to the line 7x+8y=2
Answer by josgarithmetic(39623) About Me  (Show Source):
You can put this solution on YOUR website!
What is the slope of 7x+8y=2?
Put it into slope-intercept form:
8y=-7x%2B2
y=-%287%2F8%29x%2B1%2F4---------------The equation transformed. Slope is -%287%2F8%29.

The line perpendicular to that one must have slope %2B8%2F7.

Using general form of the slope-intercept form, y=mx+b, solve for b.
b=y-mx.
Now, use your given point, and the found slope, to find the desired line containing the point and perpendicular to y=-%287%2F8%29x%2B1%2F4.

That final process:
b=5-%288%2F7%29%28-9%29
b=5%2B72%2F7
b=35%2F7%2B72%2F7
b=107%2F7
b=15%262%2F7

In slope-intercept form, you want the equation, highlight%28y=%288%2F7%29x%2B15%262%2F7%29