SOLUTION: Hello, What is the square root of (28 x(cubed)y(the the 4th power), where x=0, and y=0?

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Question 809166: Hello,
What is the square root of (28 x(cubed)y(the the 4th power), where x=0, and y=0?
Answer by josgarithmetic(39621) About Me  (Show Source):
You can put this solution on YOUR website!
(28 x(cubed)y(the the 4th power)
28x%5E3y%5E4

As given the variables,
28%2A0%5E3%2A0%5E4=0

sqrt%280%29=0