SOLUTION: the sum of the ages of David and James is 19 years. In three years, 6 times David's age will equal 4 times James' age. How old is each now?
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-> SOLUTION: the sum of the ages of David and James is 19 years. In three years, 6 times David's age will equal 4 times James' age. How old is each now?
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Question 809129: the sum of the ages of David and James is 19 years. In three years, 6 times David's age will equal 4 times James' age. How old is each now? Answer by TimothyLamb(4379) (Show Source):
You can put this solution on YOUR website! d + j = 19
d = 19 - j
6(d + 3) = 4(j + 3)
6d + 18 = 4j + 12
6d + 4 = 4j
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114 - 6j + 4 = 4j
118 = 10j
Answer:
j = 11.8
d = 7.2
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