SOLUTION: Selling cards at a fair. Cards cost $.50 ea and booth costs $20. Selling cards in sets of 12 for $10.20. How many sets of cards do I need to sell to cover my costs?

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: Selling cards at a fair. Cards cost $.50 ea and booth costs $20. Selling cards in sets of 12 for $10.20. How many sets of cards do I need to sell to cover my costs?      Log On


   

Question 808934: Selling cards at a fair. Cards cost $.50 ea and booth costs $20. Selling cards in sets of 12 for $10.20. How many sets of cards do I need to sell to cover my costs?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Selling cards at a fair. Cards cost $.50 ea and booth costs $20. Selling cards in sets of 12 for $10.20. How many sets of cards do I need to sell to cover my costs?
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Cost(x) = 20 + 0.5x dollars
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Revenue(x) = (x/12)10 dollars
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Breakeven occurs when cost = revenue::
Equation::
20 + 0.5x = (x/12)10
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Multiply thru by 12 to get
240 + 6x = 10x
4x = 240
x = 60 cards
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# of sets of 12 = 60/12 = 5
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Cheers,
Stan H.