SOLUTION: for the interval 0 through 2pi solve the equation {{{cos4xcos2x+sin4xsin2x=sqrt(3)/2}}}

Algebra ->  Trigonometry-basics -> SOLUTION: for the interval 0 through 2pi solve the equation {{{cos4xcos2x+sin4xsin2x=sqrt(3)/2}}}      Log On


   

Question 808776: for the interval 0 through 2pi solve the equation cos4xcos2x%2Bsin4xsin2x=sqrt%283%29%2F2
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
cos4xcos2x%2Bsin4xsin2x=sqrt%283%29%2F2
cos%284x-2x%29=sqrt%283%29%2F2
cos(2x)=√3/2
2x=π/6
x=π/12