Question 808723: If sin(x) = −3/5 and x is an angle in Quadrant III, find the value of tan(x) Found 2 solutions by stanbon, lwsshak3:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! If sin(t) = −3/5 and t is an angle in Quadrant III, find the value of tan(t)
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sin(t) = y/r = -3/5 implies y = -3 and r = 5
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Then x = sqrt[5^2-3^2] = sqrt(16) = 4
But x is negative in QIII so x = -4
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So, cos(t) = -4/5
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Your Problem:
tan(t) = sin(t)/cos(t) = (-3/5)/(-4/5) = 3/4
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Cheers,
Stan H.
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You can put this solution on YOUR website! If sin(x) = −3/5 and x is an angle in Quadrant III, find the value of tan(x)
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You are working with a 3-4-5 reference right triangle in quadrant III where sin>0,cos<0, tan>0.
sin(x)=-3/5
cos(x)=-4/5
tan(x)=sin/cos=-3/-4=3/4
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