SOLUTION: roger can run one mile in 21 minutes. jeff can run 1 mile in 18 minutes. if jeff gives roger a 1 minute head start, how long will it take before jeff catches up to roger? how far w

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: roger can run one mile in 21 minutes. jeff can run 1 mile in 18 minutes. if jeff gives roger a 1 minute head start, how long will it take before jeff catches up to roger? how far w      Log On

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Question 808689: roger can run one mile in 21 minutes. jeff can run 1 mile in 18 minutes. if jeff gives roger a 1 minute head start, how long will it take before jeff catches up to roger? how far will each have run?
Answer by josgarithmetic(39616) About Me  (Show Source):
You can put this solution on YOUR website!
Let m = minutes Roger runs.
Let d = distance until Roger and Jeff ran the same distance.

Runner___________speed(mile/minute)_____time__________distance
Jeff_____________1/21____________________m+1___________d=(1/21)(m+1)
Roger____________1/18____________________m_____________d=(1/18)m

%281%2F21%29%28m%2B1%29=%281%2F18%29%28m%29
Solve for m. With this, find m+1, the time for Jeff to catchup to Roger. Use m to find the value for the distance, d.