SOLUTION: The expression {{{(5x^6y^2)/(x^8y)}}} is equivalent to what

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Question 808661: The expression %285x%5E6y%5E2%29%2F%28x%5E8y%29 is equivalent to what

Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
%285x%5E6y%5E2%29%2F%28x%5E8y%29

Use the rule of subtracting exponents:

If an exponential factor of the numerator has the same base as an exponential
factor of the denominator, then

1. If the larger exponent is in the numerator, then subtract the exponent of
the denominator from the exponent in the numerator and place the resulting
exponential in the numerator, and eliminate the exponential from the
denominator.

2. If the larger exponent is in the denominator, then subtract the exponent of
the numerator from the exponent in the denominator and place the resulting
exponential in the denominator, and eliminate the exponential from the
numerator.

[In either case, subtract the smaller numerator from the larger and place
the resulting exponential where the larger exponent was, top or bottom]

Give the y the exponent of 1.

%285x%5E6y%5E2%29%2F%28x%5E8y%5E1%29

Look at the exponentials x%5E6 in the numerator and x%5E8 in the
denominator.  The larger exponent is in the denominator, so we subtract
the exponents "larger - smaller" = 8-6 = 2, and place the resulting 
exponential x%5E2 in the denominator because the larger exponent 8
was in the denominator, and eliminate the x%5E6 from the numerator:

%285y%5E2%29%2F%28x%5E2y%5E1%29

Now look at the exponentials y%5E2 in the numerator and y%5E1 in the
denominator.  The larger exponent is in the numerator, so we subtract
the exponents "larger - smaller" = 2-1 = 1, and place the resulting 
exponential y%5E1 in the numerator because the larger exponent 2
was in the numerator, and eliminate the y%5E1 in the denominator:

%285y%5E1%29%2F%28x%5E2%29

Finally we don't need to write the 1 exponent, so we end up with:

%285y%29%2F%28x%5E2%29

Edwin