Question 808637: The equation h= 7cos(pi/3 t) models the height h in centimeters after t seconds of a weight attached to the end of a spring that has been stretched and then released.
A. Solve the equation for t.
B. Find the times at which the weight is first at a height of 1 cm, of 3 cm, and of 5 cm above the rest position. Round your answers to the nearest hundredth.
C. Find the times at which the weight is at a height of 1 cm, of 3 cm, and of 5 cm below the rest position for the second time. Round your answers to the nearest hundredth.
I did solve for t.
So A would be:
h=7cos((pi/3)t)
h/7=cos((pi/3)t)
arccos(h/7)=(pi)(t)/3
t=3arccos(h/7)/pi
ANY HELP WOULD BE NICE PLEASE AND THANK YOU!!!
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! The equation h= 7cos(pi/3 t) models the height h in centimeters after t seconds of a weight attached to the end of a spring that has been stretched and then released.
A. Solve the equation for t.
I did solve for t.
-----------------------
h=7cos((pi/3)t)
h/7=cos((pi/3)t)
arccos(h/7)=(pi)(t)/3
t = [3arccos(h/7)]/pi
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B. Find the times at which the weight is first at a height of 1 cm, of 3 cm, and of 5 cm above the rest position. Round your answers to the nearest hundredth.
t(1) = [3*cos^-1(1/7)]/pi = [3*81.79]/pi = 78.10 seconds
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t(3) = ...... = 61.71
t(5) = ...... = 42.41
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C. Find the times at which the weight is at a height of 1 cm, of 3 cm, and of 5 cm below the rest position for the second time. Round your answers to the nearest hundredth.
t(1) = 265.67 seconds
t(3) = 282.06 seconds
t(5) = 301.36 seconds
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Cheers,
Stan H.
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