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Question 808564: the sum of 3 numbers is 100. find the numbers if the 2nd no. is 10 more than twice the first and 3rd no. is less than the sum of the 1st two?
answer pls this is consecutive numbers
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! the sum of 3 numbers is 100.
a + b + c 100
find the numbers if the 2nd no. is 10 more than twice the first
b = 2a + 10
:
and 3rd no. is less than the sum of the 1st two?
c < a + b
Replace b with (2a+10)
c < a + 2a + 10
c < 3a + 10
Assume
c = 3a + 9
:
I don't see how these could be consecutive\
Replace b with (2a+10) in the 1st equation
a + (2a + 10) + c = 100
3a + c = 100 - 10
3a + c = 90
replace c with 3a+9
3a + 3a + 9 = 90
6a = 90-9
6a = 81
a = 81/6
a = 13.5
has to be an integer,
assume a = 14
then
b = 2(14) + 10
b = 38
Find c
14 + 38 + c = 100
c = 100 - 52
c = 48
How about 14, 38, 48?
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