SOLUTION: Please help me solve this logarithm: log5 (2x^2 - 3x + 1) - log5 (x - 1) + log5 125 = 6. If you could, please show step by step. Thank you.

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Please help me solve this logarithm: log5 (2x^2 - 3x + 1) - log5 (x - 1) + log5 125 = 6. If you could, please show step by step. Thank you.      Log On


   

Question 808456: Please help me solve this logarithm: log5 (2x^2 - 3x + 1) - log5 (x - 1) + log5 125 = 6. If you could, please show step by step. Thank you.
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

log%285%2C+%282x%5E2+-+3x+%2B+1%29+%29-+log%285+%2C%28x+-+1%29%29+%2B+log%285%2C+125+%29=+6

log%285%2C+%282x%5E2+-+3x+%2B+1%29+%2F%28x+-+1%29%29+%2B+log%285%2C+125+%29=+6

log%285%2C+%28125%282x%5E2+-+3x+%2B+1%29+%2F%28x+-+1%29%29%29++=+6............in base 10

log%28%28125%282x%5E2+-+3x+%2B+1%29+%2F%28x+-+1%29%29%29%2Flog%285%29++=+6

log%28%28125%282x%5E2+-+3x+%2B+1%29+%2F%28x+-+1%29%29%29++=+6log%285%29

log%28%28125%282x%5E2+-+3x+%2B+1%29+%2F%28x+-+1%29%29%29++=+log%285%5E6%29.....if log same, then

125%282x%5E2+-+3x+%2B+1%29+%2F%28x+-+1%29++=+5%5E6

5%5E3%282x%5E2+-+3x+%2B+1%29+%2F%28x+-+1%29++=+5%5E6......simplify

cross%285%5E3%29%282x%5E2+-+3x+%2B+1%29+%2F%28x+-+1%29++=+5%5Ecross%286%29%5E3



%28%282x%5E2+-+2x%29-%28x+-+1%29%29+%2F%28x+-+1%29++=+125

%282x%28x-+1%29-%28x+-+1%29%29+%2F%28x+-+1%29++=+125

%28%282x-+1%29%28x+-+1%29%29+%2F%28x+-+1%29++=+125

%28%282x-+1%29cross%28%28x+-+1%29%29%29+%2Fcross%28%28x+-+1%29+%29+=+125

2x-+1+=+125

2x+=+125%2B1

2x+=+126

x+=+126%2F2

x+=+63