SOLUTION: You have an outdoor pool measuring 25 ft x 10 ft. You want to add a cement walkway around the pool. If the walkway will be 1 ft thick and you have 304 cubic feet of cement, how w

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: You have an outdoor pool measuring 25 ft x 10 ft. You want to add a cement walkway around the pool. If the walkway will be 1 ft thick and you have 304 cubic feet of cement, how w      Log On


   



Question 808314: You have an outdoor pool measuring 25 ft x 10 ft. You want to add a cement walkway around the pool. If the walkway will be 1 ft thick and you have 304 cubic feet of cement, how wide should the walkway be?
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
You have an outdoor pool measuring 25 ft x 10 ft. You want to add a cement walkway around the pool. If the walkway will be 1 ft thick and you have 304 cubic feet of cement, how wide should the walkway be?
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Area of the walkway of width w = (25+2w)*(10+2w) - 25*10
Area = 250 + 70w + 4w^2 - 250
= 4w^2 + 70w sq ft
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Vol = Area*depth
304 = 4w^2 + 70w
2w^2 + 35w - 152 = 0
Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation ax%5E2%2Bbx%2Bc=0 (in our case 2x%5E2%2B35x%2B-152+=+0) has the following solutons:

x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca

For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%2835%29%5E2-4%2A2%2A-152=2441.

Discriminant d=2441 is greater than zero. That means that there are two solutions: +x%5B12%5D+=+%28-35%2B-sqrt%28+2441+%29%29%2F2%5Ca.

x%5B1%5D+=+%28-%2835%29%2Bsqrt%28+2441+%29%29%2F2%5C2+=+3.60161932703562
x%5B2%5D+=+%28-%2835%29-sqrt%28+2441+%29%29%2F2%5C2+=+-21.1016193270356

Quadratic expression 2x%5E2%2B35x%2B-152 can be factored:
2x%5E2%2B35x%2B-152+=+%28x-3.60161932703562%29%2A%28x--21.1016193270356%29
Again, the answer is: 3.60161932703562, -21.1016193270356. Here's your graph:
graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+2%2Ax%5E2%2B35%2Ax%2B-152+%29

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w =~ 3.6 feet