SOLUTION: A ladder 2x+1 feet is positioned against a wall such that the bottom is x-1 feet away from a wall. The distance between the floor and the top of the ladder is 2x feet. Find the l

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: A ladder 2x+1 feet is positioned against a wall such that the bottom is x-1 feet away from a wall. The distance between the floor and the top of the ladder is 2x feet. Find the l      Log On


   



Question 807981: A ladder 2x+1 feet is positioned against a wall such that the bottom is x-1 feet away from a wall. The distance between the floor and the top of the ladder is 2x feet.
Find the length, in feet of the ladder;
Assume that a right angle is formed by the wall and the floor;
The length of the ladder is --------- feet?

Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
(2x+1) is the length of ladder which is the hypotenuse
2x is one leg
and x-1 is the other leg
(2x)^2+(x-1)^2= (2x+1)^2
4x^2+x^2-2x+1=4x^2+4x+1
x^2-6x=0
x^2=6x
x=6 Or x=0
x cannot be 0
5,12,13