SOLUTION: Find the exact values of theta on the interval [0degrees, 360 degrees) that make the following equation a true statement.
3 sin theta- 6 sin theta cos theta cos theta =0
Algebra ->
Trigonometry-basics
-> SOLUTION: Find the exact values of theta on the interval [0degrees, 360 degrees) that make the following equation a true statement.
3 sin theta- 6 sin theta cos theta cos theta =0
Log On
Question 807941: Find the exact values of theta on the interval [0degrees, 360 degrees) that make the following equation a true statement.
3 sin theta- 6 sin theta cos theta cos theta =0 Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! Find the exact values of theta on the interval [0degrees, 360 degrees) that make the following equation a true statement.
3 sin theta- 6 sin theta cos theta cos theta =0
***
use x for theta
(3sinx)(1-2cos^2x)=0
(3sinx)(1-2(1-sin^2x)=0
(3sinx)(1-2+2sin^2x)=0
(3sinx)(-1+2sin^2x)=0
..
3sinx=0
x=0, 180˚
..
-1+2sin^2x)=0
sin^2x=1/2
sinx=±1/√2=±√2/2
x=45˚, 135˚, 225˚, 315˚
(