SOLUTION: Peter, john and rebecca can do a job alone in 5,8, and 10 days respectively. If they all do the job together, what fraction of yhe job is done by peter?
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Question 807907: Peter, john and rebecca can do a job alone in 5,8, and 10 days respectively. If they all do the job together, what fraction of yhe job is done by peter? Answer by jim_thompson5910(35256) (Show Source):
You can put this solution on YOUR website! First we must figure how how long it will take them to get the job done if they work together.
1/5+1/8+1/10 = 1/t
8/40+5/40+4/40 = 1/t
(8+5+4)/40 = 1/t
17/40 = 1/t
17t = 40*1
17t = 40
t = 40/17
It will take 40/17 days (roughly 2.3529 days) if they work together.
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