Question 807894: the sum of four consecutive odd numbers is 128. Then the smallest number is?
Answer by jim_thompson5910(35256)   (Show Source):
You can put this solution on YOUR website! Let x be an integer
So 2x is always even
Forcing 2x + 1 to always be odd
The next odd number after that is (2x+1)+2 = 2x + 3
The next odd number after that is (2x+3)+2 = 2x + 5
The next odd number after that is (2x+5)+2 = 2x + 7
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Add up the four integers. Then set this sum equal to 128
(2x+1)+(2x+3)+(2x+5)+(2x+7) = 128
2x+1+2x+3+2x+5+2x+7 = 128
8x+16 = 128
8x = 128-16
8x = 112
x = 112/8
x = 14
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Since x = 14, we know
2x+1 = 2*14 + 1 = 29
2x+3 = 2*14 + 3 = 31
2x+5 = 2*14 + 5 = 33
2x+7 = 2*14 + 7 = 35
So the four consecutive odd integers are: 29, 31, 33, 35
The smallest number is 29
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