SOLUTION: In which direction does the parabola open that has a Vertex at (2, -5) and y-intercept at -17

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Question 807833: In which direction does the parabola open that has a Vertex at (2, -5) and y-intercept at -17
Found 2 solutions by Edwin McCravy, josmiceli:
Answer by Edwin McCravy(20055) About Me  (Show Source):
You can put this solution on YOUR website!
Let's plot the vertex and the y-intercept and see:



Now the upper point has to be the vertex, and common sense 
tells you that the only way that the y-intercept can be way down
there at -17, is for the parabola to open downward, like this:  



So this problem doesn't require any algebra knowledge, just
common sense.

Edwin

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
I would say that it opens down because the
y-intercept is more negative than the
y-coordinate of the vertex.
I should be able to prove it
--------------------------
I'll say the parabola is:
+f%28x%29+=+a%2Ax%5E2+%2B+b%2Ax+%2B+c+
The vertex is at ( 2,-5)
+%28-b%29%2F%282a%29+=+2+
+-b+=+4a+
+b+=+-4a+
------------
I can also say
+-5+=+a%2A2%5E2+%2B+b%2A2+%2B+c+
+-5+=+4a+%2B+2b+%2B+c+
+-5+=+4a+%2B+2%2A%28-4a%29+%2B+c+
+c+=+8a+-+4a+-+5+
+c+=+4a+-+5+
-----------------
And also
(0,-17)
+-17+=+a%2A0%5E2+%2B+b%2A0+%2B+c+
+-17+=+c+
-------------
+c+=+4a+-+5+
+-17+=+4a+-+5+
+4a+=+-12+
+a+=+-3+
-----------
and
+b+=+-4a+
+b+=+-4%2A%28-3%29+
+b+=+12+
-----------
+f%28x%29+=+a%2Ax%5E2+%2B+b%2Ax+%2B+c++
+f%28x%29+=+-3x%5E2+%2B+12x+-+17+
Does it go through (2,-5) ?
+-5+=+-3%2A2%5E2+%2B+12%2A2+-+17+
+-5+=+-12+%2B+24+-+17+
+-5+=+12+-+17+
+-5+=+-5+
OK
here's the plot:
+graph%28+400%2C+400%2C+-4%2C+6%2C+-20%2C+5%2C+-3x%5E2+%2B+12x+-+17+%29+