SOLUTION: A cashier has 90 dimes and Nickels in a cash drawer. If the total is 6.40, how many nickel's are in the drawer? I divided 90 into 640 my answer 2 nickels.

Algebra ->  Customizable Word Problem Solvers  -> Coins -> SOLUTION: A cashier has 90 dimes and Nickels in a cash drawer. If the total is 6.40, how many nickel's are in the drawer? I divided 90 into 640 my answer 2 nickels.      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 807704: A cashier has 90 dimes and Nickels in a cash drawer. If the total is 6.40, how many nickel's are in the drawer? I divided 90 into 640 my answer 2 nickels.
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +n+ = number of nickels
Let +d+ = number of dimes
---------------
(1) +n+%2B+d+=+90+
(2) +5n+%2B+10d+=+640+ ( in cents )
-------------------------------
(2) +n+%2B+2d+=+128+
Subtract (1) from (2)
(2) +n+%2B+2d+=+128+
(1) +-n+-+d+=+-90+
+d+=+38+
and, since
(1) +n+%2B+d+=+90+
(1) +n+%2B+38+=+90+
(1) +n+=+52+
52 nickels are in the drawer
------------------------
check:
(2) +5n+%2B+10d+=+640+
(2) +5%2A52+%2B+10%2A38+=+640+
(2) +260+%2B+380+=+640+
(2) +640+=+640+
OK