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Question 807691: graph 3x+2y=8 by using the slope and the y- intercept.
I tried 3(0)+2y=8 and got (0,4)
I then tried it for y and got (8/3,0)
I need someone to explain to me what I need to do and how to graph Please!
Found 2 solutions by Alan3354, TimothyLamb:
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! graph 3x+2y=8 by using the slope and the y- intercept.
I tried 3(0)+2y=8 and got (0,4)
I then tried it for y and got (8/3,0)
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3x+2y=8
Solve for y
y = (-3/2)x + 4
The y-intercept is 4, or (0,4)
The slope, m, is -3/2
Plot the y-int (0,4)
m = diffy/diffx = -3/2
Count down 3 squares and right 2 squares. Plot that point.
Draw a line thru them.
Answer by TimothyLamb(4379)  (Show Source):
You can put this solution on YOUR website! You need two points on the line in order to graph it.
First get the equation in slope-intercept form: y = mx + b
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3x + 2y = 8
2y = -3x + 8
y = (-3/2)x + 4
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Plug-in two different x values in the equation to get their y values, like so:
Point p1, use x=0:
y = (-3/2)(0) + 4
y = 4
p1 = (0, 4)
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Point p2, use x=2:
y = (-3/2)(2) + 4
y = -3 + 4
y = 1
p2 = (2, 1)
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To check the work, calculate the slope using the two points, like so:
slope: m = (y2 - y1)/(x2 - x1)
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m = (1 - 4) / (2 - 0)
m = -3/2
The work is correct. This slope matches the slope-intercept form above: y = (-3/2)x + 4
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Now draw a line between points p1 and p2 to graph the equation.
The line extends infinitely beyond both points.
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