SOLUTION: How would I graph 2x - 3y= 6 using intercepts?

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Question 807583: How would I graph 2x - 3y= 6 using intercepts?
Answer by waynest(281) About Me  (Show Source):
You can put this solution on YOUR website!
2x - 3y = 6
2x - 2x - 3y = 6 - 2x
-3y = -2x + 6
-3y/-3 = 2x/-3 + 6/-3
y = (2/3)x - 2
0 = (2/3)x - 2
2 = (2/3)x - 2 + 2
2 = (2/3)x
(3/2)2 = (3/2)(2.3)x
3 = x
2(3) - 3y = 6
6 - 3y = 6
6 - 6 -3y = 6 - 6
-3y = 0
y = 0
x-intercept is (3, 0)