SOLUTION: find two consecutive numbers such that 3 time the second exceeds twice the first by 57

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: find two consecutive numbers such that 3 time the second exceeds twice the first by 57      Log On


   

Question 807421: find two consecutive numbers such that 3 time the second exceeds twice the first by 57
Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
consecutive numbers: x, (x+1)

3(x+1) = 2x + 57
3x + 3 = 2x + 57
x = 54

The numbers are 54 and 55.