SOLUTION: I need help!!! A father is twice as old as his son. Twelve years ago the father was four times as old as the son was then. Determine their present ages.

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Question 807419: I need help!!!
A father is twice as old as his son. Twelve years ago the father was four times as old as the son was then. Determine their present ages.

Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
A father is twice as old as his son. Twelve years ago the father was four times as old as the son was then. Determine their present ages.
son ----------x years
father------------2x years
12 years ago
son = x-12 years
father= 2x-12
2x-12=2(x-12)
2x-12=4x-48
4x-2x=48-12
2x=36
x=18

son = 18 years
father = 2x= 36 years