SOLUTION: solve for x:
e^x - 8e^-x = 2
Ive tried to get these all in terms of base 2, but do not know what to do from there. So i had (2^0)(e^x)-(2^3)(e^-x)=2^1
Algebra ->
Exponential-and-logarithmic-functions
-> SOLUTION: solve for x:
e^x - 8e^-x = 2
Ive tried to get these all in terms of base 2, but do not know what to do from there. So i had (2^0)(e^x)-(2^3)(e^-x)=2^1
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Question 806926: solve for x:
e^x - 8e^-x = 2
Ive tried to get these all in terms of base 2, but do not know what to do from there. So i had (2^0)(e^x)-(2^3)(e^-x)=2^1 Answer by Alan3354(69443) (Show Source):
