SOLUTION: I've been trying to figure a few of these equations all day, but I can't seem to understand the how to find the slopes and graphs and I'm getting more homework than I can keep up w

Algebra ->  Graphs -> SOLUTION: I've been trying to figure a few of these equations all day, but I can't seem to understand the how to find the slopes and graphs and I'm getting more homework than I can keep up w      Log On


   



Question 80689: I've been trying to figure a few of these equations all day, but I can't seem to understand the how to find the slopes and graphs and I'm getting more homework than I can keep up with. Also is there a more simple explanation of how to find whether points are parallel or perpendicular? Is there a way I can get some one on one tutoring, either from here or another program?
-find the slope of any line perpendicular to the line through points (0,5) and
(-3,-4)
-Floor plans for a building have the four corners of a room at the points (2,3),(11,6),(-3,18) and (8,21).
Determine whether the side through the points(2,3) and (11,6) is perpendicular to the sides through the points (2,3) and (-3,18).

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
First lets find the slope through the points (0,5) and (-3,-4)
note: check out this solver to get more help with finding the slope

Solved by pluggable solver: Finding the slope


Slope of the line through the points (0, 5) and (-3, -4)



Answer: Slope is m+=+3




Since the perpendicular slope is the negative inverse of the original slope, we can say the perpendicular slope is
m%5Bp%5D=-1%2Fm where m%5Bp%5D is the perpendicular slope

So plug in m=3 to get

m%5Bp%5D=-1%2F3
So the perpendicular slope is

m=-1%2F3


---------------------------------------------------------------
"Floor plans problem"
First lets find the slope through (2,3) and (11,6)

Solved by pluggable solver: Finding the slope


Slope of the line through the points (2, 3) and (11, 6)



m+=+%28y%5B2%5D+-+y%5B1%5D%29%2F%28x%5B2%5D+-+x%5B1%5D%29


m+=+%286+-+3%29%2F%2811+-+2%29


m+=+%283%29%2F%289%29


m+=+1%2F3



Answer: Slope is m+=+1%2F3




Now lets find the slope through (2,3) and (-3,18)

Solved by pluggable solver: Finding the slope


Slope of the line through the points (2, 3) and (-3, 18)



m+=+%28y%5B2%5D+-+y%5B1%5D%29%2F%28x%5B2%5D+-+x%5B1%5D%29


m+=+%2818+-+3%29%2F%28-3+-+2%29


m+=+%2815%29%2F%28-5%29


m+=+-3



Answer: Slope is m+=+-3




Notice that the side that contains the points (2,3) and (11,6) has a slope of m=1%2F3. Also notice that the side containing (2,3) and (-3,18) has a slope of m=-3. So to see if they are perpendicular we simply invert and negate either slope. For instance, lets invert and negate the first slope m=1%2F3:

m%5Bp%5D=-1%2Fm

m%5Bp%5D=-1%2F%281%2F3%29=-3

So the perpendicular slope is -3. This shows that -3 and 1/3 are perpendicular slopes which means the two sides are perpendicular.