SOLUTION: find four consecutive integers such that five times the fourth diminished by twice the second is 7.

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Question 806876: find four consecutive integers such that five times the fourth diminished by twice the second is 7.
Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
consecutive integers: x, (x+1), (x+2), (x+3)

5(x+3) - 2(x+1) = 7
5x + 15 - 2x - 2 = 7
3x + 13 = 7
3x = -6
x = -2

The integers are -2, -1, 0, and 1.