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Question 80685: one number is 5 more than another number. Four times the larger number plus 3 times the smaller is 97. Find the numbers.
Answer by praseenakos@yahoo.com(507)   (Show Source):
You can put this solution on YOUR website! QUESTION:
one number is 5 more than another number. Four times the larger number plus 3 times the smaller is 97. Find the numbers.
ANSWER:
Assume that one number is = x
Then the other number is = x + 5
Here the larger number is x + 5
Four times the larger number is = 4(x+5)
Here the smaller number is = x
Three times the smaller number is = 3x
Four times the larger number plus 3 times the smaller is = 97
==> 4(x+5) + 3x = 97
==> 4x + 20 + 3x = 97
==> 4x+ 3x + 20 = 97
==> 7x + 20 = 97
subtract 20 from both sides of the equation
==> 7x + 20 - 20 = 97 -20
==> 7x = 77
Divide both sides of the equation by 7
==> 7x/7 = 77/7
==> x = 11.
So the first number is 11
Then the other number, which is 5 more than that of first = 11+ 5= 16
The second number is 16.
To check the answers....it is given that...Four times the larger number plus 3 times the smaller is 97
That is 4*16 + 3*11 = 64 + 33 = 97.
That is our answer is correct.
Hope you understood.
Regards.
Praseena.
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