SOLUTION: taxi fare for a 5km trip is $3.75. the fare for a 10km trip is $6.75. a.) find a linear equation for these data points b.) use this linear equation to find the fare of a 32km tr

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: taxi fare for a 5km trip is $3.75. the fare for a 10km trip is $6.75. a.) find a linear equation for these data points b.) use this linear equation to find the fare of a 32km tr      Log On


   

Question 806819: taxi fare for a 5km trip is $3.75. the fare for a 10km trip is $6.75.
a.) find a linear equation for these data points
b.) use this linear equation to find the fare of a 32km trip
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Plot the distance in km on the horizontal axis
Plot the fare for the trip on the vertical axis
Let +d+ = distance in km
Let +c+ = fare for the trip
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Use the general point slope formula
+%28+c+-+3.75+%29+%2F+%28+d+-+5+%29+=+%28+6.75+-+3.75+%29+%2F+%28+10+-+5+%29+
+%28+c+-+3.75+%29+%2F+%28+d+-+5+%29+=+3+%2F+5+
Multiply both sides by +5%2A%28+d-5+%29+
+5%2A%28+c+-+3.75+%29+=+3%2A%28+d-5+%29+
+5c+-+18.75+=+3d+-+15+
+5c+=+3d+%2B+3.75+
+c+=+.6d+%2B+.75+
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check answer:
+c+=+.6%2A5+%2B+.75+
+c+=+3.75+
and
+c+=+.6%2A10+%2B+.75+
+c+=+6.75+
OK
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+d+=+32+ km
+c+=+.6%2A32+%2B+.75+
+c+=+19.2+%2B+.75+
+c+=+19.95+
A 32 km trip costs $19.95
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