SOLUTION: I need help finding all angles where 0 is less than or equal to t and t is less than 2pi.
My problem is cos t= radical 2 divided 2. Given the bounds I know that on the quadrants,
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My problem is cos t= radical 2 divided 2. Given the bounds I know that on the quadrants,
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Question 806606: I need help finding all angles where 0 is less than or equal to t and t is less than 2pi.
My problem is cos t= radical 2 divided 2. Given the bounds I know that on the quadrants, 0 and 2pi is along the x axis and seems to be located in the middle of the 1st and 4th quadrant. Now the directions specify the given condition, so if 0 and 2pi are in the middle of those two quadrants, how would I go about finding the angles? Answer by solver91311(24713) (Show Source):
Take a look at the unit circle. The -coordinate of a point on the unit circle is the cosine of the angle formed by the ray from the origin passing through that point. Cosine is positive in the first and fourth quadrants.
