Question 806581: Find three consecutive even integers such that five times the sum of the smallest and largest integers is the same as the square of the middle number.
Answer by CubeyThePenguin(3113) (Show Source):
You can put this solution on YOUR website! consecutive even integers: (x-2), x, (x+2)
5((x-2) + (x+2)) = x^2
5(2x) = x^2
10x = x^2
0 = x^2 - 10x
0 = x(x - 10)
x = 0, x = 10
The integers could be {-2, 0, 2} or {8, 10, 12}.
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