You can put this solution on YOUR website! Find the exact value of cos t if sin t = 5/9 and t is in Quadrant 2
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sin = y/r
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If sin = 5/9, y = 5 and r = 9
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Solve for "x":
x = sqrt[9^2-5^2] = sqrt(56)
But x is negative in QII so x = -sqrt(56)
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cos(t) = x/r = -sqrt(56)/9
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Cheers,
Stan H.