SOLUTION: how do i solve 2log x = log(6-x)?

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Question 806427: how do i solve 2log x = log(6-x)?
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
2log x = log(6-x)
log x^2= log (6-x)
x^2=6-x
x^2+x-6=0
(x+3)(x-2)=0
x=-3 OR 2