SOLUTION: How do I solve the following problems logx + log1.4 =2 lnx - ln1.4 =2 and log(3x) - log1.3 = 2.4 ln(3x) + ln 1.3 = 2.4 I have tried dividing such as to find x

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: How do I solve the following problems logx + log1.4 =2 lnx - ln1.4 =2 and log(3x) - log1.3 = 2.4 ln(3x) + ln 1.3 = 2.4 I have tried dividing such as to find x       Log On


   

Question 806318: How do I solve the following problems
logx + log1.4 =2
lnx - ln1.4 =2
and
log(3x) - log1.3 = 2.4
ln(3x) + ln 1.3 = 2.4
I have tried dividing such as to find x
logx + log1.4 =2
---- ------
log log = 1.4=2 == .7
I do not think this is correct. Please show me where I am going wrong.
Thank you
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+log%28x%29+%2B+log%281.4%29+=+2+
+log%28+1.4x+%29+=+2+
The base is +10+, so
+1.4x+=+10%5E2+
+x+=+100%2F1.4+
+x+=+71.429+
--------------
check:
+log%2871.429%29+%2B+log%281.4%29+=+2+
+1.854+%2B+.146+=+2+
+2.00013+=+2+
close enough
-------------------
+ln%283x%29+%2B+ln%281.3%29+=+2.4+
+ln%28+3.9x+%29+=+2.4+
+e%5E2.4+=+3.9x+
+x+=+%28+1%2F3.9+%29%2Ae%5E2.4+
+x+=+.256%2A11.023+
+x+=+2.822+
---------------
check:
+3%2A2.822+=+8.466+
+ln%283x%29+%2B+ln%281.3%29+=+2.4+
+ln%288.466%29+%2B+ln%281.3%29+=+2.4+
+2.136+%2B+.262+=+2.4+
+2.398+=+2.4+
close enough
--------------
You get the idea now