SOLUTION: I was wondering if you could help me with this problem. I think I got some of it right myself.
Problem: The value, v, of a shopkeeprs inventory software program is given by v =
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-> SOLUTION: I was wondering if you could help me with this problem. I think I got some of it right myself.
Problem: The value, v, of a shopkeeprs inventory software program is given by v =
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Question 806271: I was wondering if you could help me with this problem. I think I got some of it right myself.
Problem: The value, v, of a shopkeeprs inventory software program is given by v = -1/3t + 3, where t is the number of years since the shopkeeper bought the program. What is the program worth six years after it is first purchased.
Graph the point that shows that the program is worth 6 years after it is first purchased.
What I have done so far:
Formula for one year: -1/3 * 1 + 3
Formula for six years: -1/3 * 6 + 3
-1/3 made into a fraction is-1 divided by -3 = 0.33 or .33
Then:
.33 * 6 = 2
2 + 3 = 5
My problem is, how do I then take this and turn it into graph points?
(if it helps, my graph I have to plot it on only goes up to 10) Answer by solver91311(24713) (Show Source):
Furthermore, there is no reason to change the fraction to a decimal.
Which makes sense because if the value is 3 at time 0, 6 years later, the value needs to be smaller because the value of things like software depreciate over time.
Mark your coordinate axes with a on the horizontal and a on the vertical. Then whatever value you select for is the first coordinate in your ordered pair, and the that results from that selection is the second coordinate in your ordered pair.
John
Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
