SOLUTION: A colony of bacteria has 6.5 X 10^6 members at 8 A.M. and 9.75 X 10^6 members at 10:30 A.M. Find its population at noon.
I used the formula N = No X 2 ^ t/d
9.75 X 10^6 = 6
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-> SOLUTION: A colony of bacteria has 6.5 X 10^6 members at 8 A.M. and 9.75 X 10^6 members at 10:30 A.M. Find its population at noon.
I used the formula N = No X 2 ^ t/d
9.75 X 10^6 = 6
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Question 80626This question is from textbook
: A colony of bacteria has 6.5 X 10^6 members at 8 A.M. and 9.75 X 10^6 members at 10:30 A.M. Find its population at noon.
I used the formula N = No X 2 ^ t/d
9.75 X 10^6 = 6.5 X 10^6 X (2)^ 2.5/d
how do i work from here? This question is from textbook
You can put this solution on YOUR website! A colony of bacteria has 6.5 X 10^6 members at 8 A.M. and 9.75 X 10^6 members at 10:30 A.M. Find its population at noon.
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Find the increase per hour:
(9.75-6.5)/2.5 = 1.3 million per hour
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From 10:30 to noon is 1.5 hrs
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1.3*1.5=1.95 million is the amount of increase between 10:30 and 12:00
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Total population will be 9.75 + 1.95 = 11.7 million
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Cheers,
Stan
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