SOLUTION: What are the values of t on the interval between [0,2pi] for the square root of 6 sin 2t + 3 tan 2t=0? Only the "6" is in a square root.

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Question 806108: What are the values of t on the interval between [0,2pi] for the square root of 6 sin 2t + 3 tan 2t=0? Only the "6" is in a square root.
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
What are the values of t on the interval between [0,2pi] for the square root of 6 sin 2t + 3 tan 2t=0? Only the "6" is in a square root.
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I assume 2t is ^2(t)
..
sqrt%286%29sin%5E2%28t%29%2B3tan%5E2%28t%29=0
sqrt%286%296sin%5E2%28t%29%2B3sin%5E2%28t%29%2Fcos%5E2%28t%29=0
sin%5E2%28t%29%28sqrt%286%29%2B3%2Fcos%5E2%28t%29%29=0
sin^2(t)=0
sin(t)=0
t=0, π
or
√6+3/cos^2(t)=0
3/cos^2(t)=-√6
cos^2(t)=3/-√6
reject(can't take sqrt of negative number)