SOLUTION: The length of a rectangle is 5 times its width. When the length is decreased by 3m and the width is increased by 2m, the area of the new rectangle is 60m squared. find the original
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Question 805895: The length of a rectangle is 5 times its width. When the length is decreased by 3m and the width is increased by 2m, the area of the new rectangle is 60m squared. find the original length and width. Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! The length of a rectangle is 5 times its width.
L = 5w
When the length is decreased by 3m and the width is increased by 2m, the area of the new rectangle is 60m squared.
(L-3)*(w+2) = 60
Replace L with 5w
(5w-3)(w+2) = 60
FOIL
5w^2 + 10w - 3w - 6 = 60
5w^2 + 7w - 66 = 0
Factors to
(5w+22)(w-3) = 0
the positive solution
w = 3 m is the original width
and
5(3) = 15 m is the length
:
:
Check this
(15-3)(3+2) =
12*5 = 60
