Question 805712: how to find all the zeros for
4x^5+12x^4-41x^3-99x^2+10x+24
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! how to find all the zeros for
4x^5+12x^4-41x^3-99x^2+10x+24
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f(x) = 4x^5+12x^4-41x^3-99x^2+10x+24
Try the factors of 24 first.
1, 2, 3, 4 & 6 (plus and minus)
f(1) = 4 + 12 - 41 - 99 + 10 + 24 = -90 NG
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Factor out any that you find.
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