SOLUTION: solve the equation for solutions over the interval [0,360) 2 sin x -3 = -csc x

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Question 805666: solve the equation for solutions over the interval [0,360)


2 sin x -3 = -csc x


Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
solve the equation for solutions over the interval [0,360)


2 sin x -3 = -csc x
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2sin(x) - 3 = -1/sin(x)
2sin%5E2%28x%29+-+3sin%28x%29+%2B+1+=+0
(2sin - 1)*(sin - 1) = 0
sin = 1
x = 90 degs
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sin = 1/2
x = 30, 150 degs