SOLUTION: f(x)=x^4-3x^3+17x^2+7x-22,[-1,0].Find the turning points using a graphing calculator.

Algebra ->  Graphs -> SOLUTION: f(x)=x^4-3x^3+17x^2+7x-22,[-1,0].Find the turning points using a graphing calculator.      Log On


   

Question 805649: f(x)=x^4-3x^3+17x^2+7x-22,[-1,0].Find the turning points using a graphing calculator.
Answer by AnlytcPhil(1806) About Me  (Show Source):
You can put this solution on YOUR website!
f(x)=x^4-3x^3+17x^2+7x-22,[-1,0].Find the turning points using a graphing calculator.
Get a TI-84

Press ON
Press CLEAR
Press WINDOW

Change the numbers so that they read:

    WINDOW
     Xmin=-3
     Xmax=3
     Xscl=1
     Ymin=-35
     Ymax=35
     Yscl=10
     Xres=1

Press Y=    (Use CLEAR to eliminate anything in there)

After \Y1=  type this

            X^4-3X^3+17X^2+7X-22

Press GRAPH

You should see a graph like this but it won't have those numbers:

graph%28400%2C300%2C-3%2C3%2C-35%2C35%2Cx%5E4-3x%5E3%2B17x%5E2%2B7x-22%29 

Press 2ND
Press CALC
Press 4

At the bottom of the screen you see 

     Left Bound?
     X=0            Y=-22

Press < (the left arrow) 10 times
Press ENTER

At the bottom of the screen you see 

     Right Bound?
     X=-.6382979  Y=-18.59571

Press > (the right arrow) 15 times
Press ENTER
Press ENTER

At the bottom of the screen you read

Minimum
X=.31914894   Y=-18.12155

The turning point is (.31914894, -18.12155)

Edwin